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x^2-57x-120=0
a = 1; b = -57; c = -120;
Δ = b2-4ac
Δ = -572-4·1·(-120)
Δ = 3729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-57)-\sqrt{3729}}{2*1}=\frac{57-\sqrt{3729}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-57)+\sqrt{3729}}{2*1}=\frac{57+\sqrt{3729}}{2} $
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